32x^2+64x-40=0

Solution for 32x^2+64x-40=0 equation:

32x^2+64x-40=0

a = 32; b = 64; c = -40;
Δ = b2-4ac
Δ = 642-4·32·(-40)
Δ = 9216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{9216}=96$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-96}{2*32}=\frac{-160}{64}
=-2+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+96}{2*32}=\frac{32}{64}
=1/2
$